SQL Start-Script generator
Sometimes it’s so simple:
import glob
files = glob.glob('*.*');
f=open('start_script.sql', 'w')
f.write('PROMPT This is an automatic generated start script\n');
f.write('PROMPT\n');
f.write('SPOOL start_script.LOG\n\n');
for filename in files:
if filename == 'start_script.sql':
continue
f.write('PROMPT Starting script ' + filename + '\n');
f.write('@@' + filename + '\n');
f.write('\nPROMPT\n');
f.write('PROMPT Finished.\n');
f.write('SPOOL OFF\n');
f.close();
exit();
Explanation:
First get a file list of the current directory (glob.glob(‘.’), this won’t return you directories since they don’t have an extension, if your files doesn’t have an extension, either: your fault). Then open a file called start_script.sql which will held our start-script (pretty self-explanatory). Then we generate a “@@” line for each file (this means if you have non-SQL-files in that directory you have to clean-up your script or edit it that it only takes .sql files (tip: glob.glob(‘*.sql’)). The start-script itself is excluded but the python script will be included (can easily be made excluded as well). After the loop the file gets closed and that’s it.
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